To set or clear a bit within a byte variable based upon a bit in the same or other byte variable try:
(byte2 &= ~BITMASK2), (byte1 & BITMASK1) ? (byte2 |= BITMASK2) : 0;
Which could be encapsulated into a macro:
#define setmask(b1, m1, b2, m2) (((b2) &= ~(m2)), ((b1) & (m1)) ? ((b2) |= (m2)) : 0)
which you would use thusly:
setmask(byte1, BITMASK1, byte2, BITMASK2);
The result for the PIC is:
bcf _byte2,3 btfsc _byte1,2 bsf _byte2,3
Which is very effecient. If you don't want to clear the bit first (e.g. if it was a port pin) then it would be:
(!(byte1 & BITMASK1) ? (byte2 &= ~BITMASK2) : 0), (byte1 & BITMASK1) ? (byte2 |= BITMASK2) : 0;
PIC - Bit operations@
|file: /Techref/language/ccpp/bittwid.htm, 1KB, , updated: 2008/3/19 02:23, local time: 2019/5/23 18:10,
|©2019 These pages are served without commercial sponsorship. (No popup ads, etc...).Bandwidth abuse increases hosting cost forcing sponsorship or shutdown. This server aggressively defends against automated copying for any reason including offline viewing, duplication, etc... Please respect this requirement and DO NOT RIP THIS SITE. Questions?|
<A HREF="http://www.sxlist.com/techref/language/ccpp/bittwid.htm"> Efficient bit twiddeling in C</A>
|Did you find what you needed?|
Welcome to sxlist.com!
& kind contributors
just like you!
Please don't rip/copy
Copies of the site on CD
are available at minimal cost.
Welcome to www.sxlist.com!